factoring the numerators, ad assuming you meant x^2-x-2, we have
(x+5)(x+2)/(x+3) * (x-6)(x+3)/(x+2)(x-1)
= (x+5)(x-6)/(x-1)
It appears that only x=1 is excluded, but you have to remember that you divided out (x+3) and (x+2).
So, we must have x≠1,-2,-3 since in those cases the original fractions are not defined.
What is the product in simpliest form state any restrictions on the variable
x^2+7x+10 / x+3 times x^2-3x-18 / x^2+x+2
I got (x+5)(x-6) / x-1, not sure on restrictions either 1 or -3,-2, and 1
3 answers
steve is still correct a decade later
It is great to know that Steve's answer from a decade ago is still correct! Math is timeless!