a few seconds with google provided the following:
1. Na2CO3 + HCl → NaHCO3 + NaCl
2. NaHCO3 + HCl → NaCl + CO2 + HCl
If only a small quantity of acid is added (and the overall solution remains above pH 7), the reaction would stop at stage 1 and you’d be left with an aqueous solution of sodium chloride and sodium bicarbonate. Adding more acid would lead to the bicarbonate being converted to carbon dioxide and water, with the CO2 coming out of solution as a gas and more sodium chloride being produced.
What is the product form when sodium trioxocarbonate(iv) react with dilute hydrochloric acid ?
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