What is the probability that an 8 digit numbers contains "97"?

Answer 1

if the first 2 digits are 97 then there are 10^6 ways of picking the other 6 digits.

Since the 97 can appear in 7 different places in an 8-digit number, that means there are 7,000,000 ways to make an 8-digit numbers with 97 in it.

Answer 2

so, that would be a probability of 7*10^6/9*10^7 = 7/90 = .0777