What is the probability that a number chosen at random from the range 1,000,000,000 to 9,999,999,999 inclusive will contain ten different digits? Round your answer to the nearest millionth

Answer 1

The number of ways the 10 distinct digits can form distinct numbers is given by
10!.
So the probability is 10! divided by the number of possible outcomes.

Answer 2

The first digit on the right can be any number from 0 to 9 so ten choices
1/10 so far
the second digit (tens place) can be one of 9
1/10 * 1/9
the third can be one of 8 remaining
1/10 * 1/9 * 1/8
etc
get the picture?

Answer 3

So after i do all that should i get one whole number

Answer 4

No, you will not get a whole number
a probability is a number between 0 and 1
1/10! which is about .00000027