complete this:
We estimate the probability by Pr( X ≥ 8) years where X is normally distributed with mean 5.24 and sd = 1.90.
Assuming normal distribution we want prob that x >=8
P(x>=8) = P(Z >= (8 - 5.24)/1.90) = P(Z >= 1.45) = 1 - P(Z<1.45) =
what is the probability by Pr( X ≥ 8) years where X is normally distributed with mean 5.24 and sd = 1.90?
HELP!!!
thank you!
2 answers
use a z-score table to find the portion of the population below 1.45 sd above the mean
looks like about .93
so prob X ≥ 8 is ... 1 - .93
looks like about .93
so prob X ≥ 8 is ... 1 - .93