What is the pressure on a swimmer 10meters below the surface of a lake?

Question

kanchan · Accepted Answer

The pressure on an object at a depth in water is given by P= atmospheric pressure + pgh , where p=density of water, h height of liquid column, g= acceleration due to gravity ,1.01×10^5 + 1000 × 9.8× 10~ 2×10^5Ans.

bobpursley · Answer

what is the weight of a column of water 1m^2 10 m high?
weight=volume*density*g=10m^3*1E3kg/m^3*9.8N/kg
pressure=weight/area= above/1m^2
= 10*1000*9.8pascal=98kPa

check all that math, then when you figure it is right, remember that 32ft of water (about 10m) is equivalent to one atmosphere (101kpa), and that depth is the column height of a water baromenter....http://practicalphysics.org/water-barometer.html

kanchan · Answer

Annegrace ,you can reply me if you are satisfied with the answer or not. You can message me anytime.I would be very happy if you do so.