What is the power dissipated by resistor R1 of the following circuit: two batteries in series (with values V1 = 20 volts and V2 = 20 volts) connected across three resistors in series with values R1 = 10k, R2 = 10k, and R3 = 20k

Question

im getting the answer 4 but i know its wrong. please help

Answer 1

I = 40V/40,000 ohms = 10^-3 A goes through each resistor, since they are in series.

The power dissipated in R1 is I^2*R1
= 10^-6*10,000
= 10^-2 watts

Answer 2

thanks got it now