sina = cos(π/2-a)
cosa = sin(π/2-a)
1+sina+icosa
= 1+cos(π/2-a) + i sin(π/2-a)
= 1 + cis(π/2-a)
There is no simple cis(x) form because of that pesky 1.
What is the polar form of 1+sina+icosa
2 answers
Yyh
1 answer