You should know 2.87 can't be right since solutions of sodium acetate are slightly basic.
Write the hydrolysis equation for acetate ion, plug in Kb for acetate (Kw/Ka) and solve for OH^-, convert to pOH, then to pH. I get something like 9 (actually a little less than 9).
What is the pH (to three figures) of a 0.1 M solution of sodium acetate given that the acid dissociation constant (Ka) of acetic acid is 1.8E-5? Hint:
I keep getting 2.87 but its wrong.
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