NaOH + HCl ==> NaCl + HOH
strong base + strong acid.
Determine mols NaOH = M x L = ??
Determine mols HCl = M x L = ??
Determine which reactant is in excess, then calculate molarity NaOH or HCl and pH from that. Post your work if you get stuck.
What is the pH of the solution created by combining 11.20 mL of the 0.10 M NaOH(aq) with 8.00 mL of the 0.10 M HCl(aq)?
1 answer
1 answer