CH3COOH is the acid.
CH3COONa is the base.
Buffer systems work because the acid uses up any base added and the base uses up any acid added. HCl is being added(0.1 mols to 1L or 0.1 M) so the reaction will be with the base, as follows:
......................CH3COONa + HCl ==>CH3COOH + NaCl
Initial...................1 M...............0...............1 M............0
add........................................0.1............
Change............-0.1...............-0.1...............+0.1.
Equilibrium........0.9...................0................1.1
Substitute the E line into the HH equation and solve for pH. Post your work if you get stuck. You should confirm this but I think pKa for CH3COOH is 4.75.
pH = pKa + log[(CH3COONa)/(CH3COOH)]
What is the pH of the buffer system after the addition of 0.10 mole of gaseous HCl to 1 L of the solution. With a buffer system containing 1.0 M CH3COOH and 1.0 M CH3COONa.
1 answer
1 answer