You did an extra step of 14-8.4.
pH= -log[H+]
-log[3.98x10^-9] = 8.400
pH=8.400
What is the pH of an aqueous solution at 25.0 °C that contains 3.98 × 10-9 M hydroxide ion?
i posted this before and i tried solving it but i get it wrong
14 = ph + - log (3.98 × 10-9)
14- 8.4 = ph
5.6 = ph
but the correct answer is 8.400
what did i do wrong?
1 answer
1 answer