What is the pH of a solution with [H+]= 4.75 x 10^-5?
I set this up as:
pH= -log[H+]
=-log (4.75 x 10^-5)
= 4.32
Is this the correct to solve this? thanks
1 answer
Yes, and 4.32 is the correct answer.
I set this up as:
pH= -log[H+]
=-log (4.75 x 10^-5)
= 4.32
Is this the correct to solve this? thanks
1 answer