100 mL x 0.1M HAc = 10 mmoles.
100 mL x 0.1M NaAc = 10 mmols.
1 mL x 0.1M NaOH = 0.1 mmol.
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......HAc + OH^- ==> Ac^- + H2O
I.....10.....0.......10
add........0.1..............
C...-0.1..-0.1.......+0.1
E.....9.9...0........10.1
Substitute the equilibrium values into the Henderson-Hasselbalch equation and solve for pH.
What is the pH of a solution when 1ml of 0.10M NaOH is added to 100ml of buffer containing 0.1M acetic acid and 0.1M sodium acetate?
1 answer
1 answer