pH+pOH=14
pH=-log(H+)
pOH=-log(OH-)
and finally, (H+)(OH-)=10^-14
in this case
OH=1E-5
H+=1E-14/1E-5 = 1E-9
pH= -logH+=9
Yes, the simple math works, but you need to know what you are doing and why.
What is the pH of a solution that has a OH- concentration equal to 1x10-5M?
14-x
14-5=9 can I use that simple of math
9?
2 answers
okay thank you
2 answers