. What is the pH of a solution in which 15 mL of 0.10 M NaOH is added to 25 mL of 0.10

M HCl?

2 answers

moles NaOH=.015*.1=.0015moles
Moles HCl=.025*.1=.0025 moles
excess acid= .0010 moles
concentration=.0010/.040 moles/liter

pH=-log(H+)=-log(.025)=1.60 pretty acidic
PH =10