Let x = solubility of Pb(OH)2 in mols/L.
Pb(OH)2 ==> Pb^2+ + 2OH^-
....x........x.......2x
Ksp = (Pb^2+)(OH^-)^2
Substitute from the chart above and solve for x, find 2x, then convert to pH.
What is the pH of a saturated solution of lead(II) hydroxide?
The Ksp= 4.0 X 10-15.
a) 4.7 b) 7.2 c) 9.0 d) 9.1 e) 9.3
What should I do to solve for this? Thank you
2 answers
? lost- what chart?