What is the pH of a 2.23 M HCHO2, formic acid, aqueous solution at 25 °C? ( Ka = 1.8E-4 )

Answer 1

............HCOOH ==> H^+ + HCOO^-
begin....... 2.23M....0.......0
change.......-x.......x........x
final......2.23-x.....x........x

Ka = (H^+)(HCOO^-(/(HCOOH)
Substitute from the ICE chart into Ka expression and solve for (H^+). Convert to pH.