since it's a strong acid all of the strong acid is converted to [H+] or [H3O+]
so
pH=
-log[H+]= -log [0.36]= 0,= 0.44
What is the pH of a 0.36 M HCl solution?
can someone help plz? I don't know how to go about figuring this out.
5 answers
typo correction (highlighted answer)
since it's a strong acid all of the strong acid is converted to [H+] or [H3O+]
so
pH=
-log[H+]= -log [0.36]= 0.44
since it's a strong acid all of the strong acid is converted to [H+] or [H3O+]
so
pH=
-log[H+]= -log [0.36]= 0.44
Full calculation not give u
-log(log0.36) how do this Pls full give full calculation
@Rahulchaudhary
First of all please understand that There are some concepts in logarithm.
one of them states that the logarithm of negative numbers is undefined.
log0.36 = -0.145
therefore log -0.45 is not possible and is undefined
Therefore, -log (log 0.36) is indefined
First of all please understand that There are some concepts in logarithm.
one of them states that the logarithm of negative numbers is undefined.
log0.36 = -0.145
therefore log -0.45 is not possible and is undefined
Therefore, -log (log 0.36) is indefined