What is the pH of a 0.20 M HF solution that is 5.8% ionized at 25 Celsius ?

A.4.45
b.0.70
C.1.93
D.1.23
E.1.40

1 answer

0.20M x 0.058 = 0.0116M = (H^+). Convert to pH.
HF ==> H^+ + F^-