What is the pH of a 0.0250 M solution of HCN? Ka = 4.0x10^-10

Answer 1

HCN >< H+ CN-

.250-x <> x+ x

4E-10=x^2/(.250-x) appx x^2/.250

[H+]= sqrt (4*.250E-10)

= 1E-5

pH= 5