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What is the pH of 0.001 moldm-3 solution of sodiumhydroxide
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0.001 M NaOH
(OH^-) = 0.001
pOH = -log(OH^-) = - log 0.001 = 3
Then pH + pOH = pKw = 14. You know pOH and pKw, solve for pH.
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