Hi Lucinda:
This is a buffer:
pH = pKa + log [base] / [acid]
pH = 9.241 + log [70.90 x 0.1300] /
[ 11.10 x 0.278]
= 9.72
For future questions, I can be reached at
(559) 709-2022
or
zdarakjian
atgmail
dotcom
Thank you
Zareh Darakjian, Ph.D.
University of California
Researcher, Instructor, Tutor
What is the pH for the solution made from 11.10 mL of 0.278 M HCl solution mixed with 70.90 mL of 0.1300 M ammonia solution ? Note that the pKa for NH4+ is 9.241
8.94
9.24
8.77
9.72
9.54
1 answer