To find the perimeter of a triangle, we need to calculate the distance between each pair of vertices and then sum them up.
Using the distance formula √((x2-x1)^2 + (y2-y1)^2), we can find the distances:
Distance PQ = √((-7-(-9))^2 + (3-2)^2) = √(2^2 + 1^2) = √(4 + 1) = √5 ≈ 2.24 units
Distance QR = √((3-(-7))^2 + (2-3)^2) = √(10^2 + 1^2) = √(100 + 1) = √101 ≈ 10.05 units
Distance RP = √((-9-3)^2 + (2-2)^2) = √((-12)^2 + 0^2) = √(144 + 0) = √144 = 12 units
Now, we can sum up the distances:
Perimeter = PQ + QR + RP = 2.24 + 10.05 + 12 ≈ 24.29
Rounding to the nearest tenth, the perimeter of triangle PQR is approximately 24.3 units.
None of the given answer choices are correct, but the closest one is 24.2 units.
What is the perimeter of △PQR
with vertices P(-9,2), Q(-7,3) and R(3,2) . Round your answer to the nearest tenth. (1 point)
Responses
24.2 units
24.2 units
19.8 units
19.8 units
27.6 units
27.6 units
5.6 units
whats the answer
1 answer