CaC2 + 2H2O --> Ca(OH)2 + C2H2
mols CaC2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CaC2 to mols C2H2
Then grams C2H2 = mols C2H2 x molar mass C2H2. This the theoretical yield (TY).
The actual yield (AY) is 13.5 grams.
%yield = (AY/TY)*100 = ?
what is the percentage yield of c2h2 with 50g of cac2 reacts with water to yield 13.5g of c2h2
2 answers
65%