Assuming 12 mL ethanol + 48 mL H2O = 60 mL (not a true assumption),
(12 mL/60)*100 = ?
b. 12 mL ethanol has a mass of
m = volume x density = 12*0.789 = about 9.46 g convert to mols = g/molar mass = about 0.205 mols. Again, assuming the volume is 60 cc (not true), then M = mol/L soln = 0.205/0.06 = ?
What is the percent by volume (% v/v) of a solution made by mixing 12 ml of ethanol (C2H5OH) with 48 ml of water?
b) Assuming the density of ethanol is 0.789g/ml, what is the molarity of this solution?
1 answer
2 answers