what is the oxidation state of iron in K4[Fe(CN)6]?

Answer 1

K = +1*4 = +4
CN = -1*6 = -6
To make K4[Fe(CN)6] neutral, Fe must be ??

Answer 2

2

Answer 3

To find the oxidation state of iron (Fe) in K4[Fe(CN)6], we can use the following equation:

Charge of the overall compound = Sum of charges of all the atoms in the compound

The charge of the potassium ion (K+) is +1 and we have four of them, so their total charge is +4.

The charge of the cyanide ion (CN-) is -1 and we have six of them, so their total charge is -6.

Let X be the oxidation state of iron (Fe).

The charge of the entire compound K4[Fe(CN)6] is 0, so we can write:

+4 + X + (-6) = 0

Simplifying and solving for X, we get:

X = +2

Therefore, the oxidation state of iron (Fe) in K4[Fe(CN)6] is +2.