What is the oxidation state of Cr in K2Cr2O4?

Answer 1

Every compound is zero.
K is 2*+1 = 2
Cr = 2*x = 2x
O = 4*-2 = -8
2 + 2x + (-8) = ?

Answer 2

CR IN K2CR2O4

Answer 3

k: 2*1
o: 4*-2
Cr : 2*x
2*1+ 4*-2+ 2*x = 0
x = +3

Answer 4

2(1)+2(x)+4(-2)=0
2-8+2x=0
2x=6
X=3