To determine the oxidation number of nitrogen in both compounds, we can follow these guidelines:
-
In ammonia (NH₃):
- The oxidation number of hydrogen (H) is +1.
- Let the oxidation number of nitrogen (N) be \( x \).
- The overall charge of the molecule is neutral (0).
- The equation can be set up as follows: \[ x + 3(+1) = 0 \] Simplifying this gives: \[ x + 3 = 0 \ x = -3 \]
- Therefore, the oxidation number of nitrogen in NH₃ is -3.
-
In nitric acid (HNO₃):
- The oxidation number of hydrogen (H) is +1, and the oxidation number of oxygen (O) is usually -2.
- Let the oxidation number of nitrogen (N) be \( x \).
- The overall charge of the molecule is neutral (0).
- The equation can be set up as follows: \[ +1 + x + 3(-2) = 0 \] Simplifying this gives: \[ +1 + x - 6 = 0 \ x - 5 = 0 \ x = +5 \]
- Therefore, the oxidation number of nitrogen in HNO₃ is +5.
In summary:
- The oxidation number of nitrogen in NH₃ is -3.
- The oxidation number of nitrogen in HNO₃ is +5.