what is the optimal condition of u(x1,x2) = 3x1+ 2x2

Answer 1

The optimal condition for a function u(x1, x2) = 3x1 + 2x2 occurs when the partial derivatives with respect to both x1 and x2 are equal to zero.

Mathematically, this can be expressed as:
∂u/∂x1 = 3 = 0
∂u/∂x2 = 2 = 0

Since the partial derivatives are constants and non-zero, there are no values of x1 and x2 that satisfy this condition. Therefore, the given function u(x1, x2) = 3x1 + 2x2 does not have an optimal condition.