Remember this.
pH + pOH = pKw = 14
You know pKw and pH, solve for pOH. Then
pOH = -log(OH^-), substitute and solve for OH^-.
What is the (OH-) when pH = 4.25
3 answers
im confused, is the answer 1.77827941x10^-10 or 5623413252????
It's 1.78E-10.
Why are you confused.
14-4.25 = 9.75 = pOH
Then pH = -log(OH^-)
-9.75 = log OH^-
OH^- = 1.78E-10
OR
OH^- = 10^-pOH
OH^- = 1.78E-10
Why are you confused.
14-4.25 = 9.75 = pOH
Then pH = -log(OH^-)
-9.75 = log OH^-
OH^- = 1.78E-10
OR
OH^- = 10^-pOH
OH^- = 1.78E-10