What is the [OH-] of a solution that has [H+]=2.45x10^-8

1 answer

To calculate the hydroxide ion concentration ([OH-]) of a solution when the hydrogen ion concentration ([H+]) is given, you can use the equation for the ion product of water:

[H+][OH-] = 1.0 x 10^-14

Given that [H+] = 2.45 x 10^-8, you can plug this value into the equation and solve for [OH-]:

(2.45 x 10^-8) [OH-] = 1.0 x 10^-14

[OH-] = (1.0 x 10^-14) / (2.45 x 10^-8)
[OH-] = 4.08 x 10^-7

Therefore, the [OH-] concentration of the solution is 4.08 x 10^-7.