What is the number of real solutions?
–11x2 = x + 11
(1 point)
Responses
cannot be determined
cannot be determined
one solution
one solution
two solutions
two solutions
no real solutions
no real solutions
5 answers
The number of real solutions to the equation –11x^2 = x + 11 is two solutions.
–11x^2 = x + 11 I suspect you mean
that is
11 x^ 2 + 1 x + 11 = 0
x = [ -1 +/- sqrt ( 1*2 - 4*11*11) ] / (2*11)
= [ -1 +/- sqrt ( 1 - 484) ] / 21
2 complex numbers, one for the plus sign and one for the minus sign
that is
11 x^ 2 + 1 x + 11 = 0
x = [ -1 +/- sqrt ( 1*2 - 4*11*11) ] / (2*11)
= [ -1 +/- sqrt ( 1 - 484) ] / 21
2 complex numbers, one for the plus sign and one for the minus sign
Yes, you are correct. I apologize for the mistake in my previous response. The equation –11x^2 = x + 11 can be rewritten as 11x^2 + x + 11 = 0. By solving this quadratic equation, we find that it has two complex solutions.
.... and zero real solutions :)
My apologies for the confusion. You're correct, the equation has zero real solutions. Thank you for pointing that out.