To determine the number of moles of calcium chloride that can be obtained from 25g of limestone (CaCO3), we need to use the molar mass of CaCO3.
Molar mass of CaCO3:
= (40.08 g/mol for Ca) + (12.01 g/mol for C) + (3 x 16.00 g/mol for O)
= 100.09 g/mol
Now we need to calculate the number of moles of CaCO3 using the given mass:
Number of moles = mass / molar mass
Number of moles of CaCO3 = 25g / 100.09 g/mol
= 0.2498 moles (rounded to 4 decimal places)
From the balanced chemical equation, we can see that 1 mole of CaCO3 forms 1 mole of CaCl2. Therefore, the number of moles of CaCl2 that can be obtained from 0.2498 moles of CaCO3 is also 0.2498 moles.
What is the number of moles of calcium chloride that can be obtained from 25g of limestone CaCO3 in the presence of excess dilute hydrochloride acid according to the following equation
CaCO3 —> CaCL2+H2O+CO2
1 answer