what is the number of atoms in the formula 8AlF3

3 answers

To determine the number of atoms in the formula \( 8\text{AlF}_3 \), we need to break down the components of the compound.

  1. The formula \( \text{AlF}_3 \) contains:

    • 1 aluminum (Al) atom
    • 3 fluorine (F) atoms
  2. Since the coefficient is 8 in front of \( \text{AlF}_3 \), we multiply the number of each type of atom by 8:

    • Aluminum: \( 8 \times 1 = 8 \) atoms
    • Fluorine: \( 8 \times 3 = 24 \) atoms
  3. Now, total the number of atoms:

    • Total atoms = number of Al atoms + number of F atoms
    • Total atoms = \( 8 + 24 = 32 \) atoms

Thus, there are a total of 32 atoms in the formula \( 8\text{AlF}_3 \).

5BaSi2O5

To determine the number of atoms in the formula \( 5\text{BaSi}_2\text{O}_5 \), we need to analyze the components of the compound.

  1. The formula \( \text{BaSi}_2\text{O}_5 \) contains:

    • 1 barium (Ba) atom
    • 2 silicon (Si) atoms
    • 5 oxygen (O) atoms
  2. Since the coefficient is 5 in front of \( \text{BaSi}_2\text{O}_5 \), we multiply the number of each type of atom by 5:

    • Barium: \( 5 \times 1 = 5 \) atoms
    • Silicon: \( 5 \times 2 = 10 \) atoms
    • Oxygen: \( 5 \times 5 = 25 \) atoms
  3. Now, total the number of atoms:

    • Total atoms = number of Ba atoms + number of Si atoms + number of O atoms
    • Total atoms = \( 5 + 10 + 25 = 40 \) atoms

Thus, there are a total of 40 atoms in the formula \( 5\text{BaSi}_2\text{O}_5 \).