what is the nth term equation for a geometric sequence with a1 = 36 and r = 1/3

Answer 1

term(9) = a(r^8) = 36(1/3)^8 = 36/6561 = 4/729

Answer 2

I really have to get new glasses, I read it as the 9th term

term(n) = 36(1/3^(n-1)
or 36(3)^(1-n)
= 4(3^2)(3^(1-n)
= 4(3)^(3-n)