What is the next number in the series?
0 1 5 14 30 __
2 answers
50
I see a recursive formula:
term(n) = term(n-1) + (n-1)^2 , for n > 1 , term(1) = 0
term(1) = 0
term(2) = 0 + 1^2 = 1
term(3) = 1 + 2^2 = 5
term(4) = 5 + 3^2 = 14
term(5) = 14 + 4^2 = 30
term(6) = 30 + 5^2 = 55
term(n) = term(n-1) + (n-1)^2 , for n > 1 , term(1) = 0
term(1) = 0
term(2) = 0 + 1^2 = 1
term(3) = 1 + 2^2 = 5
term(4) = 5 + 3^2 = 14
term(5) = 14 + 4^2 = 30
term(6) = 30 + 5^2 = 55