V1/T1=V2/T2
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What is the new volume if the volume of a gas is 3.2 L when the temperature is 7 C if the temperature is increased to 15 C without changing the pressure
2 answers
assuming the gas is ideal, we can use the formula,
V1/T1 = V2/T2
where
V1 = initial volume
T1 = initial temperature (in K)
V2 = final volume
T2 = final temperature (in K)
we first convert the given temp to Kelvin units:
T1 = 7 + 273.15 = 280.15 K
T2 = 15 + 273.15 = 288.15 K
substituting,
3.2 / 280.15 = (V2) / 288.15
V2 = 3.2 * 288.15 / 280.15
V2 = 3.29 L
hope this helps~ :)
V1/T1 = V2/T2
where
V1 = initial volume
T1 = initial temperature (in K)
V2 = final volume
T2 = final temperature (in K)
we first convert the given temp to Kelvin units:
T1 = 7 + 273.15 = 280.15 K
T2 = 15 + 273.15 = 288.15 K
substituting,
3.2 / 280.15 = (V2) / 288.15
V2 = 3.2 * 288.15 / 280.15
V2 = 3.29 L
hope this helps~ :)
3 answers