The question asks for the NET ionic equation. What you have written (correctly) is the MOLECULAR equation. To turn the molecular equation into the net ionic equation you cancel ions common to both sides. That means 2Na^+ and 2HCO3^- cancel leaving
Pb^2+(aq) + S^2-(aq) ==> PbS(s)
What is the net ionic equation form the reaction between Na2S(aq) and Pb(HCO3)2(aq)?
Just wanting to make sure this correct:
2Na+(aq) + S2-(aq) + Pb2+(aq) + 2HCO3-(aq) --> 2Na+(aq) + 2HCO3-(aq) + PbS(s)
1 answer