What is the net ionic equation for the reaction Copper (II) chloride and sodium hydroxide?

Answer 1

Write the molecular equation.
CuCl2(aq) + 2NaOH(aq) ==> Cu(OH)2(s) + 2NaCl(aq)

Then the net ionic equation follows:
Cu^+2(aq) + 2Cl^-(aq) + 2Na^+(aq) + 2OH^-(aq) ==> Cu(OH)2(s) + 2Na^+(aq) + 2Cl^-(aq)
Now cancel the ions common to both sides; i.e., cancel 2Cl^- and 2Na^+ to leave
Cu^+2 (aq) + 2OH^-(aq) ==> Cu(OH)2(s)
Check my work closely.