The molecular equation is HCOOH + NaOH ==> HCOONa + H2O
The comnlete ionic equation is (with phases)
HCOOH(aq) + Na^+(aq) + OH^(aq) ==> -HCOO^-(aq) + Na^+(aq) + H2O(l)
Now cancel those ions/molecules common to both left and right sides of the equation. The Na^+(aq) is the only common ion.
What's left is the net ionic equatio.
HCOOH(aq) + OH^-(aq) ==> HCOO^- +(aq) + H2O(l)
What is the net ionic equation for the neutralization of CHOOH with NaOH?
1 answer