What is the mole fraction of chlorine gas, Cl2, if 2.50 mol of the poisonous gas is mixed with 1.80 mol of He and 3.00 mol of Ar

Answer 1

To find the mole fraction of chlorine gas, Cl2, we first need to calculate the total moles of all gases present:

Total moles = 2.50 mol Cl2 + 1.80 mol He + 3.00 mol Ar
Total moles = 2.50 + 1.80 + 3.00 = 7.30 mol

Next, we can calculate the mole fraction of Cl2 by dividing the moles of Cl2 by the total moles:

Mole fraction of Cl2 = Moles of Cl2 / Total moles
Mole fraction of Cl2 = 2.50 mol / 7.30 mol
Mole fraction of Cl2 ≈ 0.342

Therefore, the mole fraction of Cl2 in the mixture is approximately 0.342.