Kb = (Kw/Ka) = (OH^-)(C6H5COOH)/(C6H5COO^-)
Plug in values for Kw, Ka, x for OH and x for C6H5COOH, and 5.78E-3 for C6H5COO^-) and solve for x.
What is the molarity of OH- in a 5.78×10-3 M C6H5CO2Na solution that hydrolyzes according to the equation.
C6H5CO2-(aq) + H2O(l) = OH-(aq) + C6H5CO2H(aq)
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