Ca(OH)2 ==> Ca^2+ + 2OH^-
pH = -log(H^+). Solve for H^+.
Convert to OH^-. 1/2 that will be (Ca^2+) = [Ca(OH)2]
what is the molarity of a solution of the strong base Ca(OH)2 in a solution that has a pH of 10.80?
1 answer
1 answer