To find the molarity of the solution, we need to first calculate the number of moles of RuCl3 present in 9.478 grams.
The molar mass of RuCl3 is 207.2 + (3 x 35.5) = 241.7 g/mol.
Number of moles = (Mass of compound)/(Molar mass of compound)
Number of moles of RuCl3 = 9.478 g / 241.7 g/mol = 0.0392 mol
Now we can calculate the molarity using the formula:
Molarity = (Number of moles of solute) / (Volume of solution in liters)
Molarity = 0.0392 mol / 1.00 L = 0.0392 M
Therefore, the molarity of the solution is 0.0392 M.
What is the molarity of A solution containing 9.478 Grams of RuCl3 in enough water To make 1.00 L of solution.
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