What is the molarity of a solution 12.5 naoh dissolved in total volume of 625ml?

Question

NaOH = 12.5/molar mass of NaOH = 12.5/39.99 = 0.313

molarity = no.of moles/volume in L = 0.313/0.625 = 0.501 moles/L

Answer 1

If you mean that the 12.5 NaOH is 12.5 grams of NaOH, then your answer and solution are correct. :)

Answer 2

I have to do the problem in this form.

12.5gNaOH/mol * ??/40.0NaOH * 625ml/ 1 * 1L/ 1000mL

Where am I messing uo

Answer 3

The 625 should be in the denominator.
It should be 12.5 g NaOH x (1 mol NaOH/40 g NaOH) x (1/625 mL) x (1000 mL/L) = ?

Answer 4

I see.
No, the 12.5 g shouldn't have any denominator units. The given was only 12.5 g NaOH, and this is the mass of NaOH.
You should write,
[ 12.5 g NaOH * (1 mol NaOH / 40 g NaOH) ] / [ 625 mL * (1 L / 1000 mL) ]
= 0.500 M

Sorry for the late reply. Hope this helps~ `u`

Answer 5

I got it now thanks guys :)