What is the molar solubility of barium phosphate in a 0.282M barium acetate solution?

Question

If I set up and ice table I would have 0.282M - X = ? Would I use the molar mass of barium acetate to complete the equation to find X?

Answer 1

Ba3(PO4)2 ==> 3Ba^2+ + 2PO4^3-
Ba(C2H3O2)2 ==> Ba^2+ + 2C2H3O2^-
(Ba^2+) = 3x from Ba3(PO4)2 + 0.282 from Ba(C2H3O2)
(PO4^3-) = 2x from Ba3(PO4)2
Substitute into Ksp and solve for x = molar solubility Ba3(PO4)2.