What is the molar mass of 0.500 g of unknown monoprotic acid used in titration, if 22.5 mL of 0.15 M NaOH solution was required to neutralize it?

Question

I do not need the answer, but instead an example of how to do a question just like it.

Answer 1

moles base = .0225*.15
moles acid= mass/molmass

molmass= mass/moles acid= .5/(.0225*.15)