What is the molar concentration of a solution obtained by dissolving 560cm3 of hydrogen chloride gas measured at s.t.p in 92.5cm3 of water.

Answer 1

To solve this problem, we need to use the formula:

Molarity (M) = moles of solute / volume of solution in liters

First, we need to calculate the number of moles of hydrogen chloride gas (HCl) in 560 cm3 at STP. At STP, 1 mole of any gas occupies 22.4 L of volume. Therefore, the number of moles of HCl is:

n = V / Vm = 560 cm3 / 22.4 L/mol = 0.025 mol

Next, we need to calculate the volume of the solution in liters. We know that 92.5 cm3 of water was used to dissolve the HCl gas. Therefore, the total volume of the solution is:

V = 560 cm3 + 92.5 cm3 = 652.5 cm3 = 0.6525 L

Now we can use the formula to calculate the molarity of the solution:

M = n / V = 0.025 mol / 0.6525 L = 0.038 M

Therefore, the molar concentration of the solution is 0.038 M.