What is the molality of a solution consisting of 34.0 mL of benzene (C6H6; d = 0.877 g/mL) in 187 mL of hexane (C6H14 ; d = 0.660 g/mL)?

Answer 1

from the densities, figure the grams of each.

molality=(gramsBenzene/molmassC6H6)/kg of hexane

notice the denominator is in kg.

Answer 2

654f